LeetCode 1344. Angle Between Hands of a Clock

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题目

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

Example 1:

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Input: hour = 12, minutes = 30
Output: 165

Example 2:

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Input: hour = 3, minutes = 30
Output: 75

Example 3:

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Input: hour = 3, minutes = 15
Output: 7.5

Example 4:

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Input: hour = 4, minutes = 50
Output: 155

Example 5:

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Input: hour = 12, minutes = 0
Output: 0

Constraints:

  • 1 <= hour <= 12
  • 0 <= minutes <= 59
  • Answers within 10^-5 of the actual value will be accepted as correct.

思路

Math.

代码

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class Solution(object):
    def angleClock(self, hour, minutes):
        """
        :type hour: int
        :type minutes: int
        :rtype: float
        """
        perMinute = 6
        perHour = 30
        minute_angle = perMinute * minutes
        hour_angle = (hour % 12 + float(minutes) / 60) * perHour
        res = abs(hour_angle - minute_angle)
        return min(res, 360-res)